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6d^2-5d-25=0
a = 6; b = -5; c = -25;
Δ = b2-4ac
Δ = -52-4·6·(-25)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-25}{2*6}=\frac{-20}{12} =-1+2/3 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+25}{2*6}=\frac{30}{12} =2+1/2 $
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